Question

A weightless rod is acted on by upward parallel forces

Answer 1

Answer:

hii

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Explanation:

The rod will be in equilibrium if the net force and torque on the rod will be zero.

The total force in the upward direction=4N+2N=6N

so 6N force will be downward direction.

Let x be the distance of the action of force on the rod at point D from the midpoint of the rod.and let this position is on the side of point B.Now the net torque due to these forces will be zero.The torques due to forces 2N and 6N will be in clockwise and torque due to 4N will be anticlockwise soNet torque about the mid point of the rod

2×1.5+6×x=4×1.53+6x=66x=3x=0.5 cmso distance of the position of 6N force from A and B will be respectively2cm and 1cm.hence option (d) is correct.

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Answer 2

ANSWER

A weightless rod is acted upon by upward parallel force of 2N and 4N at ends A and B respectively the total length of rod AB=3m to keep rod in equilibrium a force of 6N should act in forces acting at A and B are 2N and 4N in upward direction. So resistive force = 2+4 = 6N.