A weightless spring which has a force constant 'k' oscillates with frequency 'n' when a mass m is suspended from it. The spring is cut into two equal halves and a mass 2m is suspended from it. The frequency of oscillation will now become- a skipped n b 2n c n/ d n(2)1/2
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Given,
a weightless spring which has a force constant 'k' oscillates with frequency 'n' when a mass m is suspended from it.
The period of oscillation of mass m of a body suspended by a spring is ,
T=2π(√m/k)
Also given that,
The spring is cut into two equal halves and a mass 2m is suspended from it.
So,
k2= 2k
m2=2m
t=1/n
→n=(1/2π) * √k/m
n2= 1/ 2π *√2k/2m
= (1/2π) * √k/m
=n
Therefore,the new frequency is same as previous frequency.
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