Physics, asked by mukulgupta8069, 11 months ago

A weightlifter lifted a load of 200 kgf to a height of 2.5 metre in 5 seconds calculate:1.the work done .2.the power developed by him .
take g =10 newton/kg

Answers

Answered by pk0528355
1

Answer:

Explanation:

Work done = potential energy= mass × acceleration due to gravity× height

=200×2.5×10

=5000 J

Power = work done / time

= 5000j/5s

= 1000 W

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