Question

A well is dug 16m deep. its radius is 1.75m. the earth dug out is spread evenly on a rectangular platform which is 11m multiply with 4m find the height of platform raised

Answer 1

Given
Depth of well=16m
Radius =1.75m

The volume of earth dug=
$\pi \: {r}^{2} h$
$= \frac{22 \times 1.75 \times 1.75 \times 16}{7}$
=154m³

Volume of platform =volume of digged earth

11x4xh=154

$h = \frac{154}{11 \times 4}$
H=3.5m

This is ur ans hope it will help you in case of any doubt comment below

Answer 2

Given

Depth of well=16m

Radius =1.75m

The volume of earth dug=

\pi \: {r}^{2} hπr

2

h

= \frac{22 \times 1.75 \times 1.75 \times 16}{7}=

7

22×1.75×1.75×16

=154m³

Volume of platform =volume of digged earth

11x4xh=154

h = \frac{154}{11 \times 4}h=

11×4

154

H=3.5m

HOPE IT HELPS