A well is dug of diameter 3m and depth 7m and Earth is spread around it to form embarkment of with 0.5 m. find the height.
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Radius of the dug well= 3/2 = 1.5m
Volume of earth dug out=
π×h×r^2 = 22/7 × 7 × 1.5 ×1.5= 22×1.5^2=33×1.5m^3=49.5m^3
Let the height of the embankment be H,
vol. of embankment=πr^2H-πR^2H
=> π×1.25×H - π×4×H = 49.5
=>πH(1.25×4)=49.5
=>πH(5)=49.5
=>πH=9.9
=>H=9.9÷22/7=99×7/22×10
=>H=9×7/20=63/20=3.15m
Answer: Height of the embankment is 3.15m
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