Question

a well is dug out whose radius is 2.5 m and depth is 63 m if the earth taken out from well is spread all over a rectangular field whose dimensions are 30m* 28m find the rise in level of the rectangular field ​

Answer 1

Answer:

volume of earth taken out = volume of cylinder =

$\pi \: r {}^{2} h$

=

$\pi(2.5) { }^{2} \times 63$

now, volume of rectangular field = volume of cuboid =

$l \times b \times h$

=

$30 \times 28 \times h$

= volume of earth dug out = volume of cylinder

so,

30 x 28 x h =

$\pi \times 2.5 {}^{2} \times 63$

after solving

$h = (\pi \times 2.5 {}^{2} \times 63) \div (30 \times 28)$

h = 1.473 m