a well is dug whose diameter is 4m and the depth is 10m find the quantity of earth taken out calculate the cost of plastering of the curved (inner) surface at rupees 5.00per Sq. m
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Since, Volume of well = Volume of earth dug out and Radius of well=4/2=2m
Volume of cylindrical well or earth dug out =
Pi×2^2×10
Pi×40
22/7×40=125.66 m^2
Cost of plastering =CSA of well ×5m^2
=(2×Pi×2×10)×5
=125.71×5
=Rs.628.55
Pls
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Volume of cylindrical well or earth dug out =
Pi×2^2×10
Pi×40
22/7×40=125.66 m^2
Cost of plastering =CSA of well ×5m^2
=(2×Pi×2×10)×5
=125.71×5
=Rs.628.55
Pls
mark thanks and Brainliest
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