a well of 2 metre diameter is dug 7m deep. the earth dug out is spread evenly all around it to a width
of 5 m to form an embankment. find the height of the embankment so formed
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Let us assume shape of well is like a solid circular cylinder
Radius of cylinder, r = 2/2 = 1m
Depth(height) of well, h = 14m
Volume of right circular cylinder, V’ = π r2 h
---------(I)
Given that, length of embankment, l = 40 cm
Let width of the embankment be x m
Volume of the embankment, V’’ = π r2 h
= π ((1+x)2 – 1)2 x 0.4 -----------(II)
Since well is spread evenly to form the embankment, so their volumes, V’ = V’’
⇒ π × 14 = π ((1+x)2 – 1)2 x 0.4
⇒ x = 5m
∴ Height of the embankment, x = 5cm
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