Question

A well of diameter 3 m is dug 14 m deep The soil taken out of it is spread evenly around it to a width of 5 m, to form a embankment.

Answer 1

Answer:

Height of embankment will be 1.125 m.

Step-by-step explanation:

Depth of well = 14 m (H)

Radius (R) of extreme circular end of well =  3/2 m

Width of embankment = 4

Embankment will be in a cylindrical shape having outer radius (R) as;

4+3/2=11/2 m

and inner radius (r) as= 3/2 m

Let height of embankment be h

Volume of soil dug from well = volume of earth used to form embankment

thus,$\pi R^{2} H=\pi (R^{2}-r^{2} )h \\\pi (3/2)^{2} (14)=\pi ((11/2)^{2} -(3/2)^{2} )h\\9/4*14=112/4*h\\h=9*14/112\\   =9/8\\    =1.125 m$