Math, asked by rafiloyola9122, 1 year ago

A well of diameter 3cm and 14m deep in dug. the earth, taken out of it, has been evenly spread all around it in the shape of a circular ring of width 4m to form an embankment.find the height of embankment?

Answers

Answered by RUPANTAR
0
D=3cm
so r =3/2 cm
h=14m
=1400cm
so vol of earth taken out
=π×1.5sqare×h
=99
width of embarkment =4m
so vol=π×2×h
so
π×2×h=99
so h=π×99/2
=155.6
Answered by Anonymous
3

Step-by-step explanation:

Height of the well = 14 m.

Diameter of the well = 3m.

Therefore, Radius of the well = 3/2 m.

According to question now :

Volume of the earth taken out of the well = πr²h

=> 22/7 × 3/2 × 3/2 × 14

=> 22 × (3/2)² × 2

=> 44 × 9/4

=> 11 × 9

=> 99 cm.

Outer radius of embankment (R) = (3/2 +4)

=> 11/2 m

Now,

Area of embankment = outer area - inner area

=> πR² - πr²

=> 22/7 [(11/2)² - (3/2)²]

=> 22/7 × 112/4

=> 88 m²

Height of the embankment = Volume / Area

=> 99/88

=> 1.125 m

Therefore, the height of the embankment is 1.125 m

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