A well of diameter 3cm and 14m deep in dug. the earth, taken out of it, has been evenly spread all around it in the shape of a circular ring of width 4m to form an embankment.find the height of embankment?
Answers
Answered by
0
D=3cm
so r =3/2 cm
h=14m
=1400cm
so vol of earth taken out
=π×1.5sqare×h
=99
width of embarkment =4m
so vol=π×2×h
so
π×2×h=99
so h=π×99/2
=155.6
so r =3/2 cm
h=14m
=1400cm
so vol of earth taken out
=π×1.5sqare×h
=99
width of embarkment =4m
so vol=π×2×h
so
π×2×h=99
so h=π×99/2
=155.6
Answered by
3
Step-by-step explanation:
Height of the well = 14 m.
Diameter of the well = 3m.
Therefore, Radius of the well = 3/2 m.
According to question now :
Volume of the earth taken out of the well = πr²h
=> 22/7 × 3/2 × 3/2 × 14
=> 22 × (3/2)² × 2
=> 44 × 9/4
=> 11 × 9
=> 99 cm.
Outer radius of embankment (R) = (3/2 +4)
=> 11/2 m
Now,
Area of embankment = outer area - inner area
=> πR² - πr²
=> 22/7 [(11/2)² - (3/2)²]
=> 22/7 × 112/4
=> 88 m²
Height of the embankment = Volume / Area
=> 99/88
=> 1.125 m
Therefore, the height of the embankment is 1.125 m
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