a well of diameter 3m is dug 14m deep. the earth taken out of it has been spread evenly all around it in the shape of a circular ring of width 4m to form an embankment. Find the height of the embankment.
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Height of the well = 14 m
Diameter of the well = 3 m
So, Radius of the well = 3/2 m
Volume of the earth taken out of the well = πr²h
= 22/7 × (3/2)²*14
= 99 m³
Outer radius of the embankment = R = (3/2 + 4)m = 11/2 m
Area of embankment = Outer area - Inner area
⇒ πR² - πr²
= 22/7 × [(11/2)² - (3/2)²]
= 22/7 × [(121/4) - (9/4)]
= 22/7 × 112/4
= 88 m²
Height of the embankment = Volume/Area
= 99/88
Height of the embankment = 1. 125 m
[ Thank you! for asking the question. ]
Hope it helps!
Height of the well = 14 m
Diameter of the well = 3 m
So, Radius of the well = 3/2 m
Volume of the earth taken out of the well = πr²h
= 22/7 × (3/2)²*14
= 99 m³
Outer radius of the embankment = R = (3/2 + 4)m = 11/2 m
Area of embankment = Outer area - Inner area
⇒ πR² - πr²
= 22/7 × [(11/2)² - (3/2)²]
= 22/7 × [(121/4) - (9/4)]
= 22/7 × 112/4
= 88 m²
Height of the embankment = Volume/Area
= 99/88
Height of the embankment = 1. 125 m
[ Thank you! for asking the question. ]
Hope it helps!
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