If x and y are two positive real number such that 8x3+27y3=730 and 2x2y+3xy2=15 then evaluate 2x+3y
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8x3 + 27y3 = 730 and 2x2y + 3xy2 = 15 then evaluate 2x + 3y
(2x + 3y)3 = 8x3 + 27y3 + 18 x 2x2y + 18 x 3xy2
(2x + 3y)3 = 730 + 18 (15 ) = 730 + 270 = 1000
(2x + 3y)3 = 103
2x + 3y = 10
HOPE THIS HELPS
(2x + 3y)3 = 8x3 + 27y3 + 18 x 2x2y + 18 x 3xy2
(2x + 3y)3 = 730 + 18 (15 ) = 730 + 270 = 1000
(2x + 3y)3 = 103
2x + 3y = 10
HOPE THIS HELPS
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