a well of diameter 3M is dug 14m deep the earth taken out of it has been spread evenly all around it in the shape of circular ring of width 4m to form an embankment .find the height of the embankment
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hey here is your answer
Solution:-
Height of the well = 14 m
Diameter of the well = 3 m
So, Radius of the well = 3/2 m
Volume of the earth taken out of the well = πr²h
= 22/7*(3/2)²*14
= 99 cu m
Outer radius of the embankment = R = (3/2 + 4)m = 11/2 m
Area of embankment = outer area - inner area
⇒ = πR² - πr²
= 22/7*[(11/2)² - (3/2)²]
= 22/7*[(121/4) - (9/4)]
= 22/7 × 112/4
= 88 m²
Height of the embankment = Volume/Area
= 99/88
Height of the embankment
= 1.125 m Answer
MAKE SURE IT BRAINLIEST PLEASE
Solution:-
Height of the well = 14 m
Diameter of the well = 3 m
So, Radius of the well = 3/2 m
Volume of the earth taken out of the well = πr²h
= 22/7*(3/2)²*14
= 99 cu m
Outer radius of the embankment = R = (3/2 + 4)m = 11/2 m
Area of embankment = outer area - inner area
⇒ = πR² - πr²
= 22/7*[(11/2)² - (3/2)²]
= 22/7*[(121/4) - (9/4)]
= 22/7 × 112/4
= 88 m²
Height of the embankment = Volume/Area
= 99/88
Height of the embankment
= 1.125 m Answer
MAKE SURE IT BRAINLIEST PLEASE
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