Question

cos 30,cot 30,tan60, prove geometrically

Answer 1

hey here is your answer

If we consider any right angled triangle ADB, we have
base=BD=a,

perpendicular=AD=√3a,

hypotenuse=AB=2a and ∠ABD=60°

tan60°=AD/BD=√3a/a=√3.


The values of the trig functions of 30° and 60° can be written like this:
 (15) sin 30° = ½, sin 60° = (√3)/2. cos 30° = (√3)/2, cos 60° = ½

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