A well of diameter 3m is dug 14m deep. The soil is taken out of it is spread evenly all around it to a width of 5m to form an embankment. Find the height of the embankment
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Answered by
2
r=1.5m. ; h=14m. R=6.5cm
let height of embankment=H
Vol. of cylindrical well=vol. of embankment
πr^2h =π(R^2-r^2)H
let height of embankment=H
Vol. of cylindrical well=vol. of embankment
πr^2h =π(R^2-r^2)H
Answered by
8
Area of field
π(R^2-r^2)
π(25-2.25)
22/7(22.75)
=71.5
Volume of well
πr^2h
22/7(1.5)^2×14=99.
πr^2/πr^2h=71.5/99
25/2.25h=71.5/99.
11.11×h=71.5/99
H=71.5/99×11.11
H=0.065
π(R^2-r^2)
π(25-2.25)
22/7(22.75)
=71.5
Volume of well
πr^2h
22/7(1.5)^2×14=99.
πr^2/πr^2h=71.5/99
25/2.25h=71.5/99.
11.11×h=71.5/99
H=71.5/99×11.11
H=0.065
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