Question

A well with 10m inside in diameter is dug 14m deep . Earth taken out of it is spread all a round to a width of 5m to form an embarkment. Find the height of embarkment

Answer 1

Answer:

3.5 m

Step-by-step explanation:

Diameter of well = 10 m

Radius of well = $\frac{Diameter}{2}=\frac{10}{2}=5 m$

Depth of well = 14 m

Volume of well = $\pi r^2 h$

                         = $\frac{22}{7} \times 5^2 \times 14$

                         = $1100 m^3$

Earth taken out of it is spread all a round to a width of 5m to form an embarkment.

Radius of embarkment. = 5 m + 5 m = 10 m

let the height of embankment be h

Volume of embankment = $\pi r^2 h$

                                        = $\frac{22}{7} \times 10^2 h$

Since Earth taken out of it is spread all a round to a width of 5m to form an embarkment. So, volume of well = Volume of embankment

So,$1100=\frac{22}{7} \times 10^2 h$

$1100 \times \frac{7}{22} \times \frac{1}{10^2}=h$

$3.5=h$

Hence the height of embarkment is 3.5 m

Answer 2

Answer:

YOUR ANSWER IS 4.67 m

Step-by-step explanation:

see photo