Question

(a) What are the currents drawn by the least and the highest of the three resistors?
(b) What is the current drawn by the 6 Ω resistor?
(c) What would be the reading of the ammeter?
(d) How much current does the least of the three resistors draw from the given battery?
(e) Is the equivalent resistance of the parallel combination shown, more or less than the least
resistance, of the individual resistances?

Answer 1

I=V/R

a)2/3,2 are the currents drawn by the least and the highest of the three resistors.

b)1A

d)0.6A

e)equivalent resistance,1/R=1/4+1/6+1/12=(3+2+1)/12=6/12=1/2=0.5

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Answer 2

Answer:

a) 1.5 A and 0.5 A respectively

b) 1A

c) 3A

d) 1.5 A

e) The equivalent resistance is 3A which is higher than the least resistance of 1.5A

Explanation/Working :

a) I= V/Reff

For least resistance: I = 6/4

= 1.5 A

For the highest resistance, it is: I= 6/12

= 0.5 A

b) The current drawn by the 6 Ω

I = V/Reff

I = 6/6

= 1A

c) To find the reading of the ammeter add the current flowing through each resistor

1.5 A + 0.5 A + 1 A = 3A

d) 1.5 A it is repeated

e) The least resistance is 1.5 A

The equivalent resistance is V/R1 + V/R2 + V/R3

which gives 3A

which is higher than the least of the individual resistances of 1.5 A

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