Question

a) What is the 10th term of arithmetic sequence 5,10,15,....?

b) At what position will 100 come in this sequence?​

Answer 1

a) Common difference = -5 (as we need term from last)

20th term from the last = 150+(20−1)×−5=55

Answer 2

Answer:

A) The 10th term from the end of the A.P. -5, -10, -15,..., -1000 is -955.

Explanation:-

Here I= -1000,

d = -10-(-5)=-10+5=-5..

10th term from the end = 1 - (n - 1)

d=-1000-(10-1)(-5)=-1000 + 45

=-955

B)In 20 position

Step-by-step explanation:

Given:First term.

(a)=5second term

(t2)=10third term

(t3)=15tn=100

We know,common difference

(d)=t2-a= 10-5= 5

Now,tn=a+(n-1)dor,

100 = 5+(n-1)x5or,

100-5 (n-1)x5or,

95/5=n-1or,

19+1 = nor, n=20

Hence, 100 will came in 20 position.

Step-by-step explanation:

$hopes \: it \: helps$

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