Question

A. what is the probability of getting exactly 7 heads on 10 flips?

Answer 1

in the first flip he can either get a head or a tail hence in the first flip itself we have 2 probable outcomes. so if he flips the coin 10 times, he has 10*2 i.e. 20 total outcomes possible. so u divide 7 by 20

Answer 2

total no. of outcomes = 11(10T,0H;9T,1H;8T,2H;7T,3H;6T,4H;5T,5H;4T,6H;3T,7H;2T,8H;1T,9H;0T,10H)
so P(E)=1/11
hope this is right :)