Question

(a) What is the shape of the curve CDE
वक CDE की कौनसी आकृति है?
OParabolic (परवलय) (ii)Circle (वृत्त) (iii) straight line(सरल रेखा)
(b) If the shape of the curve ABC is represented by x²-7x+ 12, then its zeroes
are
यदि ABC वक्र को 3-7x+ 12, द्वारा दर्शाया गया है तो इसके शून्यांक होंगे।
(i)(2,-3)
( (CE) 3. 4)
(iii) (4,-5)
(IV)3,-5
(c) The path trace by the car, whose zeroes an 2 and -4 is
यदि शून्यांक 2, -4 हो तो द्विघात बहुपद होगा-
(iix-4x -8 (ii)x' +2x-8 (iii)x' +2x +B (iv):-2x+8
(d) Find number of zeroes of curve from A to E
दिये गये ग्राफ के कितने शून्यांक होंगे-
(ii)2
(iii)1
(iv)4​

Answer 1

SOLUTION

GIVEN

(b) If the shape of the curve ABC is represented by x²-7x+ 12, then its zeroes are

(i)(2,-3)

(ii) (3,4)

(iii) (4,-5)

(IV) (3,-5)

(c) The path trace by the car, whose zeroes an 2 and -4

(i) x²-4x -8

(ii) x² + 2x -8

(iii) x² + 2x + 8

(iv) x² - 2x +8

EVALUATION

(b) Here the curve is

$\sf{ {x}^{2} - 7x + 12}$

We now factorise it

$\sf{ {x}^{2} - 7x + 12}$

$\sf{ = {x}^{2} - (3 + 4)x + 12}$

$\sf{ = {x}^{2} - 3x - 4x+ 12}$

$\sf{ = x(x - 3) - 4(x - 3)}$

$\sf{ = (x - 3) (x - 4)}$

So the zeroes are 3 and 4

The correct option is (ii) (3,4)

(c) Here the zeroes are 2 and - 4

So the path is

$\sf{ = {x}^{2} - (2 - 4)x + (2 \times - 4) }$

$\sf{ = {x}^{2} + 2x - 8 }$

Hence the correct option is (ii) x² + 2x -8

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Answer 2

Answer:

a) i) Parabolic

b) ii) (3,4)

c) ii) x²-2-8

d) iv) 4

Hope it helps ;) !!