(a) What type of hybridisation is involved in the C-OH bond of alcohols and phenols?
(b) What happens when phenol is oxidised by acidified K2Cr2O7 solution?
(c) How will you distinguish 1°, 2° and 3° alcohols by Luca’s test?
Answers
Answer:
a) Alcohol has a sp3 hybrization , whereas phenol has sp2.
b)Phenol on oxidation in the presence of K2Cr2O7 is converted into carboxylic acid.
c)There is a difference in turbidity.. 3° Alcohol shows turbidity immediately after the addition of Lucas test(conc. HCL + ZnCl2) whereas 1° does not show in room temp...
hope it helps
Answer:
alcohol , phenol and ether. Both C-O-H and C-O-C bond angles in alcohols and ethers respectively are sp3 hybridised. In both the cases, oxygen atoms contain two bond pairs and two lone pairs of electrons and are oriented in a tetrahedral shape around the oxygen atom.
Explanation:
Phenol when oxidised by suitable oxidising agents like acidified sodium dichromate,a conjugated diketone i.e. benzophenone is obtained. Phenol ,first of all gives phenoxide ion,which transfers an electron to the ring. This is single electron transfer step,then laterconjugated diketone i.e. benzophenone is obtained.