A wheel at rest is rotated with a uniform angular acceleration, such that a particle on the rim of the wheel experiences a tangential acceleration of 20π ms–2. The radius of the wheel is 2 m. The instantaneous period of rotation at the end of 4 second is
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Given info : A wheel at rest is rotated with a uniform angular acceleration, such that a particle on the rim of the wheel experiences a tangential acceleration of 20π ms–2. The radius of the wheel is 2 m.
To find : The instantaneous period of rotation at the end of 4 second is ....
solution : we know, angular acceleration, α = a/r
where a is tangential acceleration and r is radius.
⇒α = 20π/2 = 10π rad/s
as wheel starts from rest, ω₀ = 0
using formula, θ = ω₀t + 1/2 αt²
⇒θ = 0 + 1/2 × 10π × (4)² = 10π × 8 = 80π rad
therefore wheel rotates 80π rad at the end of 4 sec.
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