Question

A wheel is rotating at the rate of 33 rev/min. if it comes to stop in 20s . Then the angular retardation will

be :

Answer 1

Answer:

Use w=wo+alpha(t)

wo=2πx33/60

T=20s

And w=0

Answer 2

Answer:

The angular retardation will be $\dfrac{11\pi}{200}\ rad/s^{2}$

Explanation:

Given that,

Initial angular velocity $\omega = 33\ rev/min$

Final angular velocity = 0

Time t = 20 s

We know that,

The angular velocity in rad/s

$\omega = 33\times\dfrac{2\pi}{60}$

$\omega = 1.1\pi\ rad/s$

The angular retardation will be

$\alpha = \dfrac{\omega_{i}-\omega_{f}}{t}$

Where, $\omega_{i}$= initial angular velocity

$\omega_{f}$= final angular velocity

t = time

We substitute the value into the formula

$\alpha=\dfrac{1.1\pi-0}{20}$

$\alpha=\dfrac{11\pi}{200}\ rad/s^{2}$

Hence, The angular retardation will be $\dfrac{11\pi}{200}\ rad/s^{2}$