A wheel of a car covers a distance of 3520 cm in 20 rotations. Find the radius of the
wheel?
The cost of fencing a circular race course at the rate of 28 per metre is 22112. Find the
diameter of the race course.
A path 2 m long and l m broad is constructed around a rectangular ground of
dimensions 120 m and 90 m respectively. Find the area of the path.
The cost of decorating the circumference of a circular lawn of a house at the rate of 355
per metre is 16940. What is the radius of the lawn?
Four circles are drawn side by side in a line and enclosed by a rectangle as shown below.
If the radius of each of the circles is 3 cm, then calculate:
(i) The area of the rectangle.
(ii) The area of each circle.
ii) The shaded area inside the rectangle.
Answers
R = 28 cm
Step-by-step explanation:
1. Wheel of a car covers a distance of 3520 cm in 20 rotations. Find the radius of the wheel
Circumference of Wheel = 2πR
Distance in 20 Rotation = 20 * 2πR = 3520
=> πR = 88
=> (22/7) R = 88
=> R = 28 cm
2. Cost of Fencing = 22112
Rate of Fencing = 28 per m
Length of Fencing = Circumference = 22112/28 m
Circumference = 2πR = Diameter * (22/7) = 22112/28
=> Diameter = 251.27 m
3. Area of Path = ( 120 + 2 + 2)(90 + 2 + 2) - 120 * 90 = 856 m²
4. Cost of Fencing = 16940
Rate of Fencing = 355 per m
Length of Fencing = Circumference = 16940/ 355 m
Circumference = 2πR = 2 * (22/7) * Radius = 16940/ 355
=> Radius = 7.59 m
5. Area of Rectangle = 24 * 6 = 144 cm²
Area of Each circle = πR² = 28.26 cm²
area of 4 circle = 113.04 cm²
Shaded area =144 -113.04= 30.96 cm²
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