Question

A wheel of diameter 2 m can be rotated about an axis passing through its centre by a moment of force equal to 2.0 N m. What minimum force must be applied on its rim.

Answer 1

Diameter (perpendicular distance) =2m

Moment if force =2Nm

Force =?

moment of force =diameter * force

Force = moment of force/diameter

Force=2Nm/2m

=1N

Answer 2

Answer:

2N is the correct answer.

Explanation:

perpendicular distance= diameter= 2m

                                      = radius= diameter/2

                                                   =1m

Given,

moment of force= 2.0Nm

perpendicular distance= 1m

force=?

Now,

moment of force= force * perpendicular distance

2.0Nm = F * 1m

2.0Nm/1m = F

After calculating answer will be,

2N = F

THIS IS YOUR ANSWER MATE....