Question

a wheel of diameter 2 m can be rotated about an axis passing through its center by a moment of force equal to 2.0 N m. what minimum force must be applied on its rim?

Answer 1

Answer:

Solution:

Diameter = 2m

Radius = 1m

Therefore, \bot distance = 1m

Moment of force = 2.0 Nm

Moment of force = Force \times \bot distance

2.0 Nm = 25 \times \bot distance

2.0 Nm = F \times 1 m

F = 2 N