Question

A wheel of mass 8 kg and radius of gyration 0.25 m is rotating at 300 rpm its moment of inertia is

Answer 1

Answer:

Mass = 8 kg.

Radius of the Gyration = 25 cm.

Using the Formula,

Moment of the Inertia = Radius of Gyration² × mass

∴ I = mr²

∴ I = 8 × 25 × 25 × 10⁻⁴

∴ I = 5000 × 10⁻⁴

∴ I = 0.5 Kgm⁻²

Hence, the Moment of the Inertia of the mass is 0.5.