Question

A wheel starting from rest acquires an angular velocity of 10 rad/s in two seconds. The moment of inertia of the wheel is 0.4 kg m2. Calculate the torque acting on it.

Answer 1

Answer:

2N-m

Explanation:

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Answer 2

Given:

The angular velocity of the wheel = 10 rad/s

Time taken to acquire the velocity = 2 seconds.

Moment of inertia (I) = 0.4 kgm²

To find:

The torque acting on the wheel

Solution:

From rotational motion, we know that torque is a product of the moment of inertia and angular acceleration.

Therefore the formula of the torque is,

T = Iα

where,

"T" is the torque,

"I" is the moment of inertia,

"α" is the angular acceleration.

Now to calculate the angular acceleration

$\alpha = \frac{angular \: velocity}{time} = \frac{10}{2} = 5\: rad {s}^{ - 2}$

Now, put the values in the above equation of torque.

T = 0.4 x 5

T = 2 N-m

Therefore, the torque acting on the wheel is 2 N-m