A wheel starts from rest and has angular acceleration of 4.0 rads?, Its angular velocity after 10 revolution is: (a) 16 rads (b) 22 rads1 (c) 32 rads (d) 250 rads1
and how
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Answer:
A] 16
Explanation:
By The forms of equations of rotational (circular)motion are the same as those of rectilinear motion with
s replaced by ( theta), the angular displacement.
u replaced by w0, the initial angular velocity.
a replaced by ( alpha), the angular acceleration.
Therefore.
(Theta)(rad.)= w0(rad/s)t(s) +(1/2)(alpha)(rad./s^2)t^2(s^2)…………………(1)
Data: (alpha)=2 rad./s^2,
w0=0 rad/s, since body starts the motion from rest.
t=10 s.
Substituting these values in equation (1), we have,
(Theta)(rad)=(1/2)(2)(rad/s^2)(10)^2(s^2). Then,
(Theta)(rad)=100 rad.
Now 2pi radian angular displacement gives one revolution and hence 100 rad. gives
(100/2 pi) revolutions=15.9 revolutions.
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