Question

A wheel with 6 equal parts has 2 parts with single dots. 1 part with 2 dots, 1 part with and 2 parts with no dots. What is the probability that after spinning the wheel, the arrow will come to the rest of the following parts.
(i). Part with a single dot
(ii). Part with 2 dots
(iii). Part with 3 dots
(iv). Part with no dots​

Answer 1

Step-by-step explanation:

Total no. of parts = n(s) = 6

i) part with a single dot = 2

req. probability = 2/6

ii) part with 2 dots = 1

req. probability = 1/6

iii)part with 3 dots = 1

req. probability = 1/6

iv)part with no dots = 2

req. probability = 2/6

("req." means "required"...just got shorted for easy typing...dont mind)

if this need to be explained more...come in comments...

hope this helps

Answer 2

Given : A wheel with 6 equal parts has 2 parts with single dots. 1 part with 2 dots, 1 part with and 2 parts with no dots.

To Find : probability that after spinning the wheel, the arrow will come to the rest of the following parts.

(i). Part with a single dot

(ii). Part with 2 dots

(iii). Part with 3 dots

(iv). Part with no dots​

Solution:

n(S) = 6  

A = Part with a single dot

n(A) = 2

P (A) = 2/6 = 1/3

B = Part with  two dots

n(B) =1

P (B) = 1/6 = 1/6

C = Part with three dots

n(C) =1

P (C) = 1/6 = 1/6

D = Part with no dots

n(D) = 2

P (D) = 2/6 = 1/3

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