Question

A wicket keeping glove is dropped from a height of 40m and simulateneously a ball is thrown upwards from the ground with a speed of 40m/s.When and where do they meet?

Answer 1

Answer:

t = 1s. , H = 5m.

Explanation:

let the two bodies meet at a height H from the ground after t sec. and g = 10

40 - H = gt²/2 = 5t²

H = 40t - 5t²

40 = 40t , t = 1s. , H = 5m.

Answer 2

Answer:

40 -- H = 2gh

Explanation:

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