Question

A wind electric generator is generating electrical power which flow an electric current of 2 Amp through a circut of 50 ohm. If the power of wind is 200 watt Then the efficiency of windmill is​

Answer 1

Answer:

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Answer 2

Answer:

The efficiency of the windmill is 100 %.

Explanation:

The efficiency of a body is the percentage of the work done at input being converted to the work done at the output .

The power of the windmill is 200 W.

We know that the power of the body is the product of potential difference and the current.

$P = V I .$

By Ohm's Law we have $V = I R$:

$P = ( I R ) * I$

⇒ P = I²R

Current flowing $( I ) = 2 A$.

Resistance of the circuit $( R ) = 50$Ω

$P = ( 2 )^2 * 50 W$

$P = 4 * 50\\ P = 200$

The power generated or the power output is 200 W.

Let the time for which the work is done by T.

Power is the rate of doing work which is :

$P = \frac{W}{T}\\W = P*T$

Work input

$= 200* T \\= 200 T$

Work output

$= 200* T \\\\= 200 T$

Efficiency = work output / work input × 100 %

$= \frac{200T}{200T} * 100 %\\\\ = \frac{200}{200}* 100 %\\\\ = 100 %$

The efficiency of windmill is 100 % .