A window has a height of 1m and a width of 0.5m.Two beams of width 10cm each cross the window one parallel to the width and other parallel to height .find the area of open part
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Answer:
Area of window = 1 × 0.5
= 0.5 m2
Area of beam = 2 x [( 0.1 × 1 ) + ( 0.1 × 0.5 )]
= 2 × ( 0.1 + 0.05)
=2 × 0.15
= 0.30 m2
Therefore, 0.5 - 0.3
= 0.2
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