Question

find the value of 1-2sin^a/2cos^a-1 with description​

Answer 1

Answer:

$Answer:tanAStep-by-step explanation:Given:\frac{1-cos2A+sin2A}{1+cos2A+sin2A}∴ cos 2A = (1 - sin²A)∴ cos 2A = 2 cos²A - 1∴ sin 2A = 2 sin A cos A=\frac{1-(1-2sin^2A)+2sinAcosA}{1+(2cos^2A-1)+2sinAcosA}=\frac{1-1+2sin^2A+2sinAcosA}{1+2cos^2A-1+2sinAcosA}=\frac{2sin^2A+2sinAcosA}{2cos^2A+2sinAcosA}=\frac{2sinA(sinA+cosA)}{2cosA(sinA+cosA)}=\frac{sinA}{cosA}=\boxed{tanA}$

Step-by-step explanation:

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