Question

A wire 10 cm long and carrying a current of 1.5A is held in a uniform magnetic field in which B= 10-3 T. Calculate the force on the wire if it is held perpendicular to the lines of the magnetic field.

Answer 1

F=Bil sin90 ,as held perpendicular
F=10.3×1.5×0.1
F=+1.545N

Answer 2

Answer:

Explanation:

Given :-

Length of the wire, L = 10 cm = 0.10 m

Current, I = 1.5 A

Magnetic induction, B = 10⁻³ T

To Calculate :-

Force, F = ??

Formula to be used :-

Force, F = BIL

Solution :-

Substituting the given values, we get

⇒ F = BIL

⇒ F = 10⁻³ × 1.5 × 0.1

⇒ F = 15 × 10⁻⁵ N.

Hence, the force on the wire if it is held is 15 × 10⁻⁵ N.