Question

A wire 300 cm long and .625 sq. cm in cross – section is found to stretch 0.3 cm
under a tension of 1200 kilograms. What is the Young’s modulus of the material
of the wire?

Answer 1

Answer:

Young's Modulus of the material of the wire,

$\\ y = \frac{fl}{a.dl} \\ = \frac{1200 \times 9.8 \times 300}{0.625 \times 0.3} \\ = \frac{3,528,000}{0.625 \times 0.3} = 18,816,000$