Question

A wire 3m long and 4.87×10^-4 m^2in cross section
is stretched
by
2mm under a load
of 1187 kg
find the value of Y.
​

Answer 1

Answer:

3656*10^7

Explanation:

AS WE KNOW

∆L = F.L/AY

Y=F.L/∆L

AND BY SOLVING WE GET YOUNG MODULUS AS 3656*10^7