Question

A wire 48 cm long is bent to form a square . Find the side of square. ​

Answer 1

Answer:

$\huge\pink{Answer}$

Given that, a wire, when bent, is able to enclose a square having area

484 cm

2

We know that, area of square

=

side

2

484=

a 2

a= 22cm

We know that perimeter of the square

=

4a

= 4 × 2 2

= 8 8 c m

Therefore the length of the wire

=

88 cm

Now,

given that the same wire is bent into a form of circle

circumference of circle = length of the wire

2πr=88

2×

7

22

×r=88

r=

2 2 × 2

8 8 × 7

r=14cm

Area of circle

=πr

2

=

7

22

×

(14) 2

=

7

22

×14×14=

7

22

×196=616 cm

2

Hence, the area of the circle is 616 cm

2

Answer 2

Answer:

A  48 cm long wire is bent to form a square. Hence the side of the square is 12 cm.

Step-by-step explanation:

• The perimeter of a square can be defined as the total length of its boundary . The perimeter of any closed geometrical shape is calculated by finding the total distance around that particular shape.
• For a square, the perimeter is calculated by finding the sum of all its sides. All four sides of a square are equal and it is the four times of the length of each side of the square.

• A wire 48 cm long which is bent to form a square. So the perimeter of the square id 48 cm.

• Let the side of the square be a cm.

• The perimeter of the square is = 4 × a cm. = 4a cm.

• According to the Given problem ,

      4a = 48 cm

   ⇒ a  = $\frac{48}{4}$ cm. = 12 cm.

• So, each side of that square is 12 cm. long.

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