Question

a wire a wire is bent in the form of a square of side 16.5 cm.it is straightened and then bent into a circle,what is thr the radius of the circle so formed ?

Answer 1

hey mate


Here's your answer

Simply we will find the perimeter

Perimeter of square
=4 X S
= 4 X 16.5
= 66 cm

Perimeter of Square = circumference of circle

2πr = Circumference of circle
2 x 22/7 X r = 66
44/7 X r = 66
r = 66 X 7/44
= 10.5 cm

Hence, r = 10.5 cm


Hope this helps you.
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Answer 2

Answer:

Side of the square = 16.5 cm

Length of the wire = Perimeter of the square =

4= (4×16.5) cm

= 66 cm

Circumference of the wire = Length of the wire

$= > 2\pi \: r \: = 66 = > 2 \times \frac{22}{7} \times r = 66$

$= > r = \frac{66 \times 7}{2 \times 22} = \frac{462}{44} = 10.5cm$

Hope it helps