Math, asked by uday618, 1 year ago

cot^2theta - 1/sin^2theta

Answers

Answered by ishanit
7
hey mate,
see my answer
______❣______

 =  >  \cot {}^{2} (\theta)  -  \frac{1}{ \sin {}^{2} (\theta) }
 =  >  \cot {}^{2} (\theta)  -  \cosec {}^{2} (\theta)
 =  >  - ( \cosec {}^{2} (\theta)  -  \cot {}^{2} (\theta) )
 =  >  - (1)
___________❤_________

hope this helps you
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ishanit: ask if any doubt
jerome7: ok
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ishanit: my answer is correct
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Answered by bgss2302
2

Cot^2theta-cosec^2theta

(cosec square theta-cot square theta =1)

cot square theta -cosec square theta =-1

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