Question

A wire bent in the form of a circle of radius 42 cm is again bent in the form of a square. what is the ratio of the region enclosed by the circle and the square

Answer 1

Answer:

Step-by-step explanation:

perimeter of the square= circumference of the circle

4×side= 2πr

4×side=2×22/7×42

4×side=2×22×6

Side=66cm

then the area of square=(side)²

=(66)²

=4356cm²

and the area of circle=πr²

=22/7×42×42

=22×6×42

=5544cm²

then ratio=5544/4356

=14/11

=14:11

I hope this may be helpful for u.

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Answer 2

Circle of radius = 42 cm

$area \: of \: circle = \pi {r}^{2}$
Thus area = 22/7 x 42 x 42 = 5544cm^2

Circumference of circle
$2\pi \: r$
= 2 x 22/7 x 42 = 264 cm

Perimeter of square = 4a = 264 cm

Side of square = 264/4 = 66 cm

Area = 66 x 66

Ratio = area of circle : area of square

= (22 x 6 x 42)/(66 x 66)

= 14:11

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