A wire bent in the form of a square of side 16.5m. It is straightened and then bent into a circle. What is the radius of the so circle formed???
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Answered by
22
Perimeter of square= Perimeter of circle.......(1)
Side, a= 16.5m
Perimeter of square= 4a = 16.5*4 = 66m...........(2)
Perimeter of circle= 2πr
2πr = 66...........(from(1)
2*(22/7)*r = 66
r= (66*7)/(2*22)
r= (21/2)
radius= 10.5 or (21/2)
hope this helps you
Side, a= 16.5m
Perimeter of square= 4a = 16.5*4 = 66m...........(2)
Perimeter of circle= 2πr
2πr = 66...........(from(1)
2*(22/7)*r = 66
r= (66*7)/(2*22)
r= (21/2)
radius= 10.5 or (21/2)
hope this helps you
Answered by
6
16.5=2*22/7*R
16.5*44/7=R
165/10*44/7=R
103.7=R
16.5*44/7=R
165/10*44/7=R
103.7=R
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