A wire bent in the shape of a square
with side 11cm was straightened out
and bent in the shape of a circle. Find the radius and area convered by the circle
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Given :
- A wire bent in the shape of a square with side 11cm was straightened out and bent in the shape of a circle
To find :
- Radius and area covered by the circle
Knowledge required :-
→ Formula of perimeter of square :-
- Perimeter of square = 4 × side
→ Formula of Circumference of circle :-
- Circumference = 2πr
→ Formula of area of circle :-
- Area of circle = πr²
where,
- Take π = 22/7
- r = radius of he circle
Solution :
Perimeter of the square :-
⠀⠀⠀⇒ Perimeter = 4 × 11
⠀⠀⠀⇒ Perimeter = 44
Periemter of square = 44 cm
Periemter of the square = Circumference of the circle
So, circumference of circle = 44 cm
⠀⠀⠀⇒ Circumference = 2πr
⠀⠀⠀⇒ 44 = 2 × 22/7 × r
⠀⠀⠀⇒ 44 = 44/7 × r
⠀⠀⠀⇒ 44 × 7/44 = r
⠀⠀⠀⇒ 7 = r
Radius of the circle = 7 cm
Area of circle :-
⠀⠀⠀⇒ Area = πr²
⠀⠀⠀⇒ Area = 22/7 × 7 × 7
⠀⠀⠀⇒ Area = 22 × 7
⠀⠀⠀⇒ Area = 154
Area of the circle = 154 cm²
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