The length of a rectangular hall is 9 metres more than its breadth.If the perimeter of the
hall is110m, find its:
(a) length (b) breadth
Answers
Step-by-step explanation:
length= x+9 and breadth=x, 2(x+9+x)=110m,4x+18=110m,4x=92m,x=23m,x+9=32m
Given :
- The length of a rectangular hall is 9 metres more than its breadth
- Perimeter of the hall = 110 m
To find :
- Length of the hall
- Breadth of the hall
Knowledge Required :-
→ Formula of perimeter of rectangle :-
- Perimeter = 2(l + b)
where,
- l = length of the rectangle
- b = breadth of the rectangle
Solution :
Here, we are given that length of the rectangular hall is 9 m more than its breadth. So, firstly we will assume any variable as the breadth of the rectangular hall and for length we will add 9 m in the variable.
Let,
- Breadth of the rectangular hall = x m
- Length of the rectangular hall = x + 9 m
Substituting the values in the formula of perimeter of rectangle,
⠀⠀⠀⇒ 110 = 2(x + 9 + x)
⠀⠀⠀⇒ 110/2 = x + 9 + x
⠀⠀⠀⇒ 55 = 2x + 9
⠀⠀⠀⇒ 55 - 9 = 2x
⠀⠀⠀⇒ 46 = 2x
⠀⠀⠀⇒ 46/2 = x
⠀⠀⠀⇒ 23 = x
The value of x = 23
Substitute the value of x in the breadth and length of the rectangular hall.
→ Length = x + 9 = 23 + 9 = 32 m
→ Breadth = x = 23 m
━━━━━━━━━━━━━━━━━━
⠀⠀⠀⠀⠀⠀⠀Verification :-
Perimeter = 110
Substitute the value of length and breadth in the formula of periemter of rectangle to verify their values.
⠀⠀⠀⇒ 2(32 + 23)
⠀⠀⠀⇒ 2(55)
⠀⠀⠀⇒ 110
Perimeter = 110
Hence, verified.