Physics, asked by vaishnavisanil2006, 1 month ago

A wire carries a current of 0.2 A for 20 seconds . If the potential difference between the two ends of the wire is 20 V , find the work done in this process​

Answers

Answered by subhsamavartj
0

Answer:

I = 0.2 A

t = 2 s

V = 20 V

W = VQ = V (It) = 20 (0.2)(2) = 8 J

Explanation:

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