Question

A wire carrying a current of 5a is placed perpendicular to a magnetic induction of 2t. The force on each cm of the wire is

Answer 1

we know, $\bf{\vec{F}=i(\vec{l}\times\vec{B})}$
where B is magnetic induction, l is length of current carrying wire , i is current and F is magnetic force .

if current carrying wire is placed perpendicular to a magnetic induction.
then, angle between l and B = 90°
so, F = Bil
F = 2T × 5A × l
F/l = 10N/m

hence, force per metre = 10N
so, force per centimetre = 10/100 = 0.1N

Answer 2

Answer:

Explanation:

we know,

where B is magnetic induction, l is length of current carrying wire , i is current and F is magnetic force .

if current carrying wire is placed perpendicular to a magnetic induction.

then, angle between l and B = 90°

so, F = Bil

F = 2T × 5A × l

F/l = 10N/m

hence, force per metre = 10N

so, force per centimetre = 10/100 = 0.1N

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