A wire forming a rectangle of remmaining side 9cm and 6.4 cm is stretched and bent again to form a circle what would the diameter of circle be
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Perimeter of rectangle = 2×(9+6.5)
And perimeter of rectangle is equal to circumference of circle. Therefore circumference of circle = 2πr. =2×(9+6.5). Therefore , 22/7 ×r = 15.5 therefore r=15.5 ×7/22=4.9 cm. Hence radius =4.9cm and diameter = 9.8cm
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