A wire given potential difference at both ends large current flowing in the current wire is 5A amount of charge that flows within 10 seconds is
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Answered by
1
i = 5 A
t = 10 s
Q = __ ?
i = Q / t
→ Q = i t
= (5 A) (10 s)
= 50 C
t = 10 s
Q = __ ?
i = Q / t
→ Q = i t
= (5 A) (10 s)
= 50 C
Answered by
0
Charge = current× time
charge = 5A×10sec= 50C
charge = 5A×10sec= 50C
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