Question

A wire has a mass (0.30.003) g, radius(0.50.005)mm and length(60.06)cm. The maximum percentage error in the measuremen

Answer 1

Answer:

Since density is mass÷volume,

For a cylinder it becomes- mass÷(pi×radius^2×length)

Relative percent errors for-

Mass-0.003÷0.3×100=1%

Radius^2-2×0.005÷0.5×100=2%

Length-0.06÷0.6×100=1%

THE UNITS CANCEL THEMSELVES FROM THE NUMERATOR AND DENOMINATOR.

therefore,

maximum percentage error in density-1%+2%+1%=4%

so, the answer is 4%