A wire has resistance of 12ohm . it is bent in a cirle what is the resustance
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Hey.
Here is the answer.
as, R = p L/A
so, R is directly proportional to L
so, the ratio of two semicircular parts will be 12/2 ohm or 6 ohm.
Now as the are bent in circle say connected at the diameter apart points
so, they are in parallel connection
1/r = 1/6 + 1/6
or, 1/r = 2/6 = 1/3
Hence, r = 3 ohm.
Thanks.
Here is the answer.
as, R = p L/A
so, R is directly proportional to L
so, the ratio of two semicircular parts will be 12/2 ohm or 6 ohm.
Now as the are bent in circle say connected at the diameter apart points
so, they are in parallel connection
1/r = 1/6 + 1/6
or, 1/r = 2/6 = 1/3
Hence, r = 3 ohm.
Thanks.
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